Webthat cos ⁡ (x) = 1 5 and x terminates in quadrant IV, we can use the Pythagorean identity to find sin ⁡ (x): sin ⁡ ( x ) = − 1 − cos 2 ( x ) = − 1 − ( 1 5 ) 2 = − 4 5 = − 2 5 Since sin ⁡ x is negative in 4 th quadrant. WebThe quadrant determines the sign on each of the values. sin(x) = opposite hypotenuse sin ( x) = opposite hypotenuse Find the adjacent side of the unit circle triangle. Since the …

5) If \( \sin (\theta)=-3 / 5 \) and \( \theta \) Chegg.com

Webfind sin2x, cos2x, tan2x if sinx = 3/sqr10 and x terminates in quadrant II This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer Question: … WebQuestion 995648: Find sin2x, cos2x, and tan2x if cosx= -15/17 and x terminates in quadrant III Answer by ikleyn(47972) (Show Source): You can put this solution on YOUR website!. marketplace distributing

Solved find sin2x, cos2x, tan2x if tan = - 12/5 and x Chegg.com

WebQuestion: 5) If \( \sin (\theta)=-3 / 5 \) and \( \theta \) terminates in the fourth quadrant, find \( \cot (\theta) \) Show transcribed image text. Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their subject area. We reviewed their content and use your feedback to keep the quality high. WebMath Trigonometry Trigonometry questions and answers Find sin 2x, cos 2x, and tan 2x if cos x = 3/sqrt (13) and x terminates in quadrant IV This problem has been solved! You'll get a detailed solution from a subject matter expert … WebJul 5, 2024 · Let $A$ be in the fourth quadrant and let $\sec (A) = \dfrac {13} {5}$, Let $B$ be in the third quadrant and let $\csc (B)=\dfrac {-5} {3}$. Find $\sin (A + B)$ and determine in which quadrant $A + B$ terminates. $\sec (A) = \dfrac {13} {5} \Rightarrow \cos (A) = \dfrac {5} {13}$ $\csc (B) = \dfrac {-5} {3} \Rightarrow \sin (B) = \dfrac {-3} {5}$ marketplace discovery strategy failed eclipse