2024 From secret import flag e bit

From secret import flag e bit

Author: saqe

August undefined, 2024

WebSo user input is concatenated with the flag and then encrypted using AES-128 in ECB mode . AES itself is a secure block cipher but ECB mode of operation is not secure. As stated on Wikipedia: The disadvantage of this method is a lack of diffusion. Because ECB encrypts identical plaintext blocks into identical ciphertext blocks, it does not hide ... WebDec 21, 2024 · We know e, n, encription algorythm and encrypted flag data from the output file. So we can reuse the available data and encryption algorythm to encrypt all the …

N1CTF 2024 checkin - crypto-writeup-public

WebFeb 19, 2024 · from math import gcd from Crypto.Util.number import bytes_to_long, isPrime from secret import p, q, x1, y1, x2, y2, e, flag # properties of secret variables assert … WebRookie Mistake - HTB import os from Crypto.Util.number import bytes_to_long, getPrime from sympy import * from secret import flag flag1 = bytes_to_long (flag [: len ... make a scan code for free

N1CTF 2024 checkin - crypto-writeup-public

WebJul 6, 2024 · Here is The encryption script from Crypto.Util.number import * from gmpy2 import * from secret import flag import os N=2048 N_e = N/2 N_k = 22 p = getPrime(N_e) while True: E = getPrime(N_e) ... Stack Overflow. About; Products For Teams; Stack Overflow Public questions & answers; WebJul 12, 2024 · our goal to get the flag string, as you can see the key is randomly choosen with 16 byte length. so every time we connect to the server, the key will change. but we can always doing encrypt because the while True KEY = Random.new().read(16) now,in the encrypt function, our flag will appended with our input plaintext WebMar 5, 2024 · from Crypto.Cipher import AES from secret import FLAG def gen_curve(bits = 40, k = 4): assert bits*k >= 160, "Error: p**k must be at least 160 bits." p = … make a scarecrow face

from secret import flag-from secret import flag文档介绍内容

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WebAug 2, 2024 · On the server there will be a file secret.py that contains the flag. We are of course not provided with the real file, so for testing locally you need to create your own … WebMar 22, 2024 · This article offers a writeup for the zer0pts CTF 2024’s crypto challenge, “Anti-Fermat.” crypto# Anti-Fermat#. description: I invented Anti-Fermat Key Generation for RSA cipher since I'm scared of the Fermat's Factorization Method. files:# task.py make a scarecrow ideasWebUtil. number import * from secret import exp, flag, nbit assert exp & ( exp + 1) == 0 def adlit ( x ): l = len ( bin ( x ) [ 2 :]) return ( 2 ** l - 1) ^ x def genadlit ( nbit ): while True : p = getPrime ( nbit ) q = adlit ( p) + 31337 if isPrime ( q ): return p, q p, q = genadlit ( nbit ) e, n = exp, p * q c = pow ( bytes_to_long ( flag ), e, n … make a scarecrow osrs

"WebSep 25, 2024 · As you can see, it encrypts the flag with a key that we don’t know. Then save the encrypted flag inside flag.enc. First bug. Notice that the generate_key function return array k and the value must be <= 255. Because it perform AND bitwise operation, therefore the generated key must be <= 255. Second bug. We can predict the value of … " - From secret import flag e bit

From secret import flag e bit

WebUtil. number import * from secret import exp, flag, nbit assert exp & (exp + 1) == 0 def adlit (x): l = len (bin (x)[2:]) return (2 ** l-1) ^ x def genadlit (nbit): while True: p = getPrime … WebfromCrypto.PublicKeyimportRSAfromCrypto.Util.numberimport*fromsecretimportewithopen("flag.txt",'r')asf:flag=f.read().strip()p=getPrime(128)q=getPrime(128)whilep%e!=1:p=getPrime(128)whileq%e!=1:q=getPrime(128)n=p*qm=bytes_to_long(flag.encode())c=pow(m,e,n)print(f"Ciphertext: …

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Webfrom secret import flag p = getPrime(512) q = getPrime(512) n = p*q x = 2024*p+1120*q h = (inverse(x,n)+x)%n e = 65537 c = pow(bytes_to_long(flag), e, n) print('n =', n) print('c =', c) print('h =', h) print('p0 =', p >> 490) 概要 RSA x = 2024p + 1120q x = 2024p +1120qとして h = (x + x^ {-1}) \mod n h = (x+x−1) mod nと p pの上位20bit程度( p_0 p0）が与えられてい … WebThe thing it is importing is a string from a file named "secret.py" in the same dir. Content of that file can look like: FLAG = "HTB{testflag}" This imported variable/string is then used …

WebAug 2, 2024 · On the server there will be a file secret.py that contains the flag. We are of course not provided with the real file, so for testing locally you need to create your own secret.py in which you define the variables flag and key. Artf7 October 20, 2024, 2:23pm #4 Fun challenge! Learned a lot of it Thanks @willwam845 ! Webfrom Crypto.Util.number import *. from secret import flag. p = getPrime(512) q = getPrime(512) n = p*q. x = 2024*p+1120*q. h = (inverse(x,n)+x)%n. e = 65537. c = …

WebFeb 14, 2015 · Complete answer is: gpg --import private.key. Given the KEYID (e.g FA0339620046E260) from the output: gpg --edit-key {KEY} trust quit # enter … WebMay 9, 2024 · from secret import flag #从secret导入flag import random #引入random函数（用于生成随机数） from Crypto. Util. number import * #引入Crypto.Util.number模块 …

WebMar 5, 2024 · from fastecdsa.curve import Curve from fastecdsa.point import Point from Crypto.Util.number import getPrime from Crypto.Random.random import randrange BITS = 80 while True: p = getPrime(BITS) if p % 4 == 3: break a, b = randrange(1, p), randrange(1, p) C = Curve("FCSC", p, a, b, 0, 0, 0) while True: xP = randrange(1, p) yP = (xP ** 3 + a …

WebDec 21, 2024 · Unfortunately running the script quickly reveals, that the secret library is missing, so we can’t just execute the script and win. Exploit. To exploit the problem, we will modify the existing code. We know e, n, encription algorythm and encrypted flag data from the output file. So we can reuse the available data and encryption algorythm to ... make a scarecrow kids make a scarecrow printableWebFeb 22, 2024 · from Crypto.Util.number import bytes_to_long, getStrongPrime from secret import flag assert len (flag) == 255 e = 3 p = getStrongPrime ( 1024, e=e) q = getStrongPrime ( 1024, e=e) n = p * q phi = (p - 1) * (q - 1 ) d = pow (e, - 1, phi) enc_d = pow (d, e, n) enc_phi = pow (phi, e, n) enc_flag = pow (bytes_to_long (flag), e, n) print ( f"{n … make a scan code for a websiteWebIn most cases the CTF challenges code does not include the flag, for obvious reasons. People simply make a file secret.py next to the challenge code, and put a variable flag inside. You should do the same. This way when you distribute the code to the players, you don't need to change anything, you simply don't include the secret.py file. make a scarecrow templateWebBrief explanation of the code: First 16 bits is used as salt for a 17-bit LFSR (bit 1 is added at position 4) Last 24 bits is used as salt for a 25-bit LFSR (bit 1 is added at position 4) For each round of clocking, 2 bits from specific positions of LFSR are xored. The output is then prepended to the LFSR register (as MSB) and LSB of register ... make a scarecrow maskWebNov 8, 2024 · from random import getrandbits from secret import flag def keygen(): p = getPrime (512) q = getPrime (512) n = p * q phi = (p-1)* (q-1) while True: a = getrandbits (1024) b = phi + 1 - a s = getrandbits (1024) t = -s*a * inverse (b, phi) % phi if GCD (b, phi) == 1: break return (s, t, n), (a, b, n) def enc(m, k): s, t, n = k r = getrandbits (1024) make a scarecrow hatWebOct 9, 2024 · 20241008-鹤城杯-CryptoSecPartWriteUp. Posted on 2024-10-09 Edited on 2024-09-10 In CTF-Crypto , WriteUp Symbols count in article: 4k Reading time ≈ 4 mins. make a scarf in blender