If 1 x 4 x then evaluate x2 +1/x2
WebSolution: Let I = ∫ x4−x2+1x2+1 dx = ∫ x2+x21 −11+x21 dx = ∫ (x−x1)2+1(1+x21) dx Let x − x1 = t and (1+ x21)dx = dt ∴ I = ∫ t2+1dt = tan−1t+c = tan−1 (x− x1)+c = tan−1 ( xx2−1)+c Web26 jul. 2024 · Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and …
If 1 x 4 x then evaluate x2 +1/x2
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Web1/16x2-1/9=0 Two solutions were found : x = 4/3 = 1.333 x = -4/3 = -1.333 Step by step solution : Step 1 : 1 Simplify — 9 Equation at the end of step 1 : 1 1 (—— • (x2)) - — = 0 … Web23 jan. 2024 · Answer Find out f (f (x)) . To prove As given in the question f (x) = x² + 1 Now f (f (x)) = f (x² + 1) Now find out the value of f (x² + 1). f (f (x)) = f (x² + 1) = (x² + 1)² + 1 Using formula (a + b)² = a² + b² + 2ab Apply in the above function f (f (x)) = (x² + 1)² + 1 Simplify Thus the value of f (f (x)) is . Advertisement
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Web25 jun. 2024 · Evaluate: ∫(x2 - 1)/(x2 + 4) dx. Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Web15 mrt. 2024 · Now, to find x^4, we can square both sides of the equation x^2 + 1/x^2 = 18: (x^2 + 1/x^2)^2 = 18^2 Expanding the left-hand side, we get: x^4 + 2 + 1/x^4 = 324 Subtracting 2 from both sides, we get: x^4 + 1/x^4 = 322 Therefore, if x - 1/x = 4, then x^2 + 1/x^2 = 18 and x^4 + 1/x^4 = 322. Your response is private Was this worth your time?
Web12 jun. 2024 · Given: x + (1/x) = 4. NOTE: since there are squared terms in the expression we're trying to evaluate, we should consider squaring both sides. Square both sides: [x + …
Web26 okt. 2015 · So x is the x in e^x and n is the total value when up to nth term is added. So for example, myexp(3,5) is going to be e^3 added up to 5th term. Thus, the higher the n is, the more accurate e^3 is going to be. canon printer check warranty by serial numberWebAnswer to 1. Evaluate for . Hint: Substitute for . 2. Given that in an... Expert Help. Study Resources. Log in Join. Walden University. COLLEGE AL. COLLEGE AL 1600 1. Evaluate for . Hint: Substitute for . 2. Given that in an... Get more out of your subscription* canon printer community nameWeb12 jul. 2024 · Given an integer X, the task is to print the series and find the sum of the series Examples : Input: X = 2, N = 5 Output: Sum = 31 1 2 4 8 16 Input: X = 1, N = 10 Output: Sum = 10 1 1 1 1 1 1 1 1 1 1 Recommended: Please try your approach on {IDE} first, before moving on to the solution. canon printer color imageclass mfb44cdwWeb3 okt. 2024 · More Answers (1) You can use the symbolic toolbox to generate eig () on the matrix with Symbolic x1 and x2, and then you can matlabFunction that and pass the handle into the objective function. You would also calculate the g functions with respect to each of the four eigenvalues, and pass those handles as well. canon printer cleaning utilityWebDetermine the interval of convergence. (Give your power series representation centered at x = 0.) f (x) = Step 1 We wish to express f (x) = 42x in the form Step 3 4-x - Σ 1-r n=0 = Step 2 Factor a 9 from the numerator and a 4 from the denominator. This will give us the following. f (x) = Therefore, f (x) = 4-X 1- Now, we can use r = X4 r=t in ... canon printer color not workingWebIf x+1/x=5, evaluate the statement Y=x^4+1/x^4 CALCULATIONS Let's solve the “sufficient condition” first: x+1/x=5 (x^2+1)/x=5 x^2+1=5x x^2-5x+1=0 By the quadratic formula, x= [- (-5) +/- √ (-5)^2–4 (1) (1)]/2 (1) x= (5 +/- √25–4)/2 x= (5 +/- √21)/2 x= (5+√21)/2, (5-√21)/2 (decimal fraction: 4.791288 to 6d. p, 0.208712 to 6d. p) PROOF flags with red and whiteWeb3 feb. 2014 · Consider (x – 1/x) = 9 Squaring on both the sides, we get [x – (1/x)] 2 = 3 2 x 2 – 2 (x) (1/x) + (1/x 2) = 9 x 2 – 2 + (1/x 2) = 9 Therefore, x 2 + (1/x 2) = 9 + 2 = 11 Recommend (0) Comment (0) Like NextGurukul? Also explore our advanced self-learning solution LearnNext flags with red in them