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Mov ax word ptr buf

Nettet30. jan. 2024 · 分析题 卷.doc,一、填空题(每题3分,共351分) 1. 现有程序段如下: mov al,x and al,0fh jz l momv byte ptr flg,1 jmp m l:mov byte ptr flg,0 m:… 请回答:该程序段完成的功能是什么? 检测x中的低4位是否全为0,如果是则1送flg,否则0送flg。 2. 假设(ax)=45ach,变量val中存放的内容为78bah,确定下列各条指令单独 ...

题目 1 判断对错,并指出原因 MOV SS∶[BX+DI],1000H MOV …

Nettet这条指令的功能是:. 将16位寄存器AX中的数据,复制传送到变量X所指向的两个字节16位存储单元中。. 本来,若变量X定义成了16位的字类型变量(即用DW定义),可以直接 … NettetStep 1 - Upload a file. Select a file from your computer using the browse function. Step 2 - Choose a destination format. Choose a destination format like MOV, 3G2, 3GP, 264, … empowered pronunciation https://salermoinsuranceagency.com

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Nettet在程序中,如果需要以另一种数据类型来访问某一存储单元时,可用强制属性操作符ptr来实现。但如果在程序中要经常以某种其它的数据类型来访问该存储单元的话,那么,就必 … Nettet8. apr. 2024 · dosgroup:deviobuf mov word ptr [ioscnt],1 mov word ptr [deviobuf],ax iofunc2: test [si.fcb_devid],080h jnz iotodev jmp iotofile iotodev: invoke save_world push ds push ss pop es push ss pop ds assume ds:dosgroup xor bx,bx mov [iocall.reqstat],bx mov byte ptr [iomed],bl mov bx,offset dosgroup:iocall mov cx,(devrd shl 8) or drdwrhl // i am … Nettet4. jun. 2010 · A)MOV BUF1,BUT2 B)MOV CS,AX C)MOV CL,1000H D)MOV DX,WORD PTR [BP+DI] 5.下面指令中,源操作数的寻址方式为直接寻址的指令是 ( A)ADDAX,WORD PTR [BX+SI] B)ADD AX,B C)INC CX D)MOV BX,7FFFH 6.下面表示段定义结束的命令是 ( A)ENDPB)ENDS C)ENDM D)END 7. … drawing wiff waffles wheelz

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Mov ax word ptr buf

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Nettetmov ax,dx mov cx,bx mov dx,bx mov dx,es 学习文档 jmp cx 图3.10 段内间接寻址示意图 学习文档 jmp word ptr [bx] ds 8 0 0 0 bx + 1000 81000 31000h 操作码 32000h 操作码 cs 3 0 0 0 ip + 2000 32000 81000h 00h 20h 图3.10 段内间接寻址示意学习图文(档cs内容不变,仅改变ip值) 3.2.1 数据传送指令 1. Nettet15. mar. 2024 · Solution 1. The instruction mov eax, eax may be a no-operation code but that is not what you have here. You're loading from memory, as indicated by the [] …

Mov ax word ptr buf

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Nettet4. jan. 2024 · ;.386 DOSSEG .MODEL SMALL .STACK 100h .DATA MY_MUL MACRO X,Y,Z mov z,0 mov z+2,0 mov ax,x mul y mov z,ax mov z+2,dx mov ax,x+2 mul y … Nettet29. aug. 2024 · mov QWORD PTR [rbp-0x30],0x4020c5 means exactly "move 0x4020c5 to a memory location rbp-0x30 and treat this number as qword" (8 - byte number). But q …

Nettet18. mar. 2006 · mov DWORD PTR [ebp-4], 0 followed directly by mov DWORD PTR [ebp-4], 1 mov DWORD PTR [ebp-4], 2 etc. Not always in sequence by value, but usually. I … Netteta) 10h b) 20hc) 30h d) 40h;执行下面的程序段后,data1单元的值是_____。 data1 db 10h,20h data2 db 30h,40h mov ax,word ptr data1 cmp ax,word ptr data2 ja mai…

Nettet6. nov. 2024 · ptr – pointer (指针)缩写。汇编里面 ptr 是规定的字 (保留字)。mov ax,bx ;是把BX寄存器“里”的值赋予AX,由于二者都是word型,不用wordmov ax,word ptr … Nettet11. jan. 2011 · entry datay table mov datax taba 指令系统程序设计举例例1:从存储器中取数的基本方法执行下列指令后,AX寄存器中的内容是什么?TABLEDW10,20,30,40,50ENTRYDWMOVBX,OFFSETTABLE;取数据串偏移地址ADDBX,ENTRY;BX=BX+3MOVAX, [BX];物理地址=DS16+(BX)答案: …

Netteta、cl b、cx c、al d、ax 答案:b 7:完成对字单元 buf 的内容加 1 运算,下面错误的指令是( ) a、mov bx,buf inc bx mov buf,bx b、mov bx,offset buf inc word ptr [bx] c、mov bx,buf inc word ptr [bx] d、mov bx,0 inc word ptr buf[bx] 答案:c 8:num equ 80h da db 34h and da,num 上述语句执行后,da 中的内容是 ( )。

Nettet1. apr. 2010 · 第四章 数据传送、寻址和算术运算. 1、操作数的三种基本类型是什么?. 立即操作数、寄存器操作数、内存操作数. 2、(真假)mov指令的目的操作数不能为段寄存器。. 假. 3、(真假)mov指令中的第二个操作数是目的操作数。. 假. 4、(真假)eip寄存器不能作为mov ... drawing wiff waffles unboxingNettet실시간 공지사항. 새소식 지존도 이제 엑스퍼트; 새소식 전문가가 필요할 때! 엑스퍼트. 새소식 봄맞이 답변 이벤트 참여하세요! empowered puppy programNettet4. jul. 2024 · 43 7. WORD PTR [d] is verbose way of saying [d] since the size of the data doesn't matter in getting its address. Would be the same as saying LEA AX, [d] which … empowered prosthetics and orthoticsNettet执行下面的程序段后,data1单元的值是_____。 data1 db 10h,20h data2 db 30h,40h mov ax,word ptr data1 cmp ax,word ptr data2 ja main mov bx,word ptr data2 … drawing windows app templateNettetmov eax, 5 sub eax, 6 eax = FFFFFFFFh, SF = 1 (The result is negative) In the following code, the value in AL is intended to be a signed byte. Explain how the Overflow flag helps, or does not help you, to determine whether the final value in AL falls within a valid signed range. mov al, -1 add al, 130 drawing wiff waffles zenpopNettetA. MOV DA1,DA2 B. JMP WORD PTR [BX] C. MOV AX, [BX+DI] NUM D. TEST AL,08H 8. 计算机处理问题中会碰到大量的字符、符号,对此必须采用统一的编码。 目前,微机中普遍采用的是(C)。 A. BCD 码 B. 二进制码 C. ASCII 码 D. 十六进制码 9. 设变量定义如下:DA_WORD DW 3,5AH,98,0B0H。 指令ADD AL,TYPE … empower ed rapid cityNettet6. mar. 2024 · You convert value in ax to decimal. The ax contains low word of file length from previous hex conversion call. So for files of length up to 65535 (0xFFFF = maximum 16b unsigned integer) it may work. For longer files it will not, as upper word is in dx, which you just destroy by mov dx,0. empowered readers literacy project